Question

What if i want to have an array of pointers to a function and the size of the array is not known from the beginning? I’m just curious if there’s a way to do that. Using new statement or maybe something else. Something looking similar to

void (* testArray[5])(void *) = new void ()(void *);

Answer 1

You could use a std::vector:

#include <vector>

typedef void (*FunPointer)(void *);
std::vector<FunPointer> pointers;

If you really want to use a static array, it would be better to do it using the FunPointer i defined in the snippet above:

FunPointer testArray[5];
testArray[0] = some_fun_pointer;

Though i would still go for the vector solution, taking into account that you don’t know the size of the array during compilation time and that you are using C++ and not C.