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Home/ Questions/Q 8997971
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:57:42+00:00 2026-06-15T23:57:42+00:00

What I’m looking for is a two dimensional array of Strings. Where Strings in

  • 0

What I’m looking for is a two dimensional array of Strings. Where Strings in the same row should be unique, but with allowing row duplicates.

I’m using a list where each row is a set:

List<Set<String>> bridges = new ArrayList<Set<String>>();

I have a method that returns a set of strings:

Set<String> getBridges(){
    Set<String> temp = new HashSet<String>();
    // Add some data to temp
    temp.add("test1");
    temp.add("test2");
    temp.add("test3");
    return temp;
}

Now in the main method, I’ll call getBridges() to fill the list that I have:

List<Set<String>> bridges = new ArrayList<Set<String>>();

Set<String> tempBridge = new HashSet<String>();

for(int j=0;j<5;j++){
            for(int k=0;k<8;k++){
                        // I call the method and store the set in a temporary storage
                tempBridge = getBridges();
                        // I add the the set to the list of sets
                bridges.add(tempBridge);
                        // I expect to have the list contains only 5 rows, each row with the size of the set returned from the method
                System.out.println(bridges.size());
            }
}

Why I’m getting the list as a one dimensional array of the size 5*8? how to fix this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T23:57:43+00:00Added an answer on June 15, 2026 at 11:57 pm

    You need to fix your loop:

    List<Set<String>> bridges = new ArrayList<Set<String>>();
    
    Set<String> tempBridge = new HashSet<String>();
    
    for(int j=0;j<5;j++){    
        tempBridge = getBridges();
        bridges.add(tempBridge);
        System.out.println(bridges.size());
    }    
    
    
    Set<String> getBridges(){
        Set<String> temp = new HashSet<String>();
        for(int k=0;k<8;k++){
            // Add some data to temp
            temp.add("test" + Integer.toString(k));
        }
        return temp;
    }
    
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