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Home/ Questions/Q 7843425
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T16:32:46+00:00 2026-06-02T16:32:46+00:00

What I’m trying to do is create a slideshow by grabbing database information and

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What I’m trying to do is create a slideshow by grabbing database information and putting it into a javascript array. I am currently using the jquery ajax function to call information from a separate php file. Here is my php code:

mysql_connect('x', 'x', 'x') or die('Not Connecting');
mysql_select_db('x') or die ('No Database Selected');

$i = 0;
$sql = mysql_query("SELECT comicname FROM comics ORDER BY upldate ASC");

while($row = mysql_fetch_array($sql, MYSQL_ASSOC)) {
echo "comics[" .$i. "]='comics/" .$row['comicname']. "';";
$i++;
}

What I want is to create the array in php from the mysql query and then be able to reference it with javascript in order to build a simple slideshow script. Please let me know if you have any questions or suggestions.

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  1. Editorial Team
    Editorial Team
    2026-06-02T16:32:48+00:00Added an answer on June 2, 2026 at 4:32 pm

    Ok have your .php echo json_encode('name of your php array');

    Then on the javascript side your ajax should look something like this:

    $.ajax({
            data:       "query string to send to your php file if you need it",
            url:        "youphpfile.php",
            datatype:   "json",
            success:    function(data, textStatus, xhr) {
                            data = JSON.parse(xhr.responseText);
                            for (i=0; i<data.length; i++) {
                            alert(data[i]); //this should tell you if your pulling the right information in
    
                            }
            });
    

    maybe replace data.length by 3 or something if you have alot of data…if your getting the right data use a yourJSArray.push(data[i]); I’m sure there’s a more direct way actually…

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