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Home/ Questions/Q 7086697
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T07:34:56+00:00 2026-05-28T07:34:56+00:00

What I’m trying to do is running a .java source by compiling and running

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What I’m trying to do is running a .java source by compiling and running it from command prompt (not using any IDE) using commands javac and java and the program connects with MySQL, so everytime I run the program from cmd, I need to specify path of the MySQL connector using -classpath switch of java. And entire command to run the program gets something like below:

java -class .;path/to/connector/mysql-connector.jar MySQLConnect

where I want it to be as simple as for other programs like java MySQLConnect
and it should run the program.

Is there any way I can add the connector’s path to environment variables of Windows that java make use of it. I already tried by creating a new CLASSPATH variable in Windows environment variables and added absolute path of the connector with file name along, but that didn’t worked.

Please provide me the workaround of this Windows and Ubuntu as well.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-28T07:34:56+00:00Added an answer on May 28, 2026 at 7:34 am

    WIndows : Copy mysql-connector.jar to C:\Program Files\Java\jdk1.6.0\jre\lib\ext
    and copy the same file to C:\Program Files\Java\jre1.6.0\lib\ext

    go to My Computer -> Properties -> Advanced -> Environment Variables

    Set these paths

     JAVA_HOME  
     C:\Program Files\Java\jdk1.6.0
    
     PATH 
     C:\Program Files\Java\jdk1.6.0\bin;
    
     CLASSPATH
     .;C:\Program Files\Java\jre1.6.0\lib\ext\mysql-connector.jar;.;
    

    open a fresh command propmpt

    type
    java -version press Enter

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