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Home/ Questions/Q 5977715
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:24:38+00:00 2026-05-22T21:24:38+00:00

What I’m trying to do is scan over every header on one sheet (the

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What I’m trying to do is scan over every header on one sheet (the headers are located in “1:1”), find a header called “Dealer Code”, then copy that entire column to another sheet.

My current problem is that there are blanks in the Dealer Code column so the selection stops. I would work from the bottom of the sheet upward to avoid this, but since the header cell is stored in an address, I can’t extract the column letter.

There a way I can include blanks in my selection, or extract the column letter and work upwards?

If I’m approaching the problem very inconveniently, please let me know! I want to learn as much as possible.

Below is my code. Help would be greatly appreciated.

'Copies over Dealer Codes
With Sheets("Raw Data").Range("1:1")
Set c = .Find("Dealer Code", LookIn:=xlValues)
If Not c Is Nothing Then
    firstAddress = c.Address
    Do
        Set c = .FindNext(c)
    Loop While Not c Is Nothing And c.Address <> firstAddress
End If

Sheets("Raw Data").Range(firstAddress).Select
Sheets("Raw Data").Range(Selection, Selection.End(xlDown)).Select
Selection.Copy (Sheets("Copied Data").Range("A1"))
End With
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  1. Editorial Team
    Editorial Team
    2026-05-22T21:24:38+00:00Added an answer on May 22, 2026 at 9:24 pm

    Try something like this:

    Sub Test()
        With ActiveSheet.Range("1:1")
        Set c = .Find("Dealer Code")
        Dim column As String
        column = Mid(c.Address, 2, 1)
        Range(column & ":" & column).Select
        End With
    End Sub
    

    This selects the whole column, but is easily changed to select the elements from the 2nd row down to the end. Since you have blanks, something like Range(column & "2:" & column & Range(column & "65536").End(xlUp).Row).Select works, but is a bit kludgey, I’ll admit.

    Other solutions may be more optimal.

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