Question

What is a good way to format a python decimal like this way?

1.00 –> ‘1’
1.20 –> ‘1.2’
1.23 –> ‘1.23’
1.234 –> ‘1.23’
1.2345 –> ‘1.23’

Answer 1

If you have Python 2.6 or newer, use format:

'{0:.3g}'.format(num)

For Python 2.5 or older:

'%.3g'%(num)

Explanation:

{0}tells format to print the first argument — in this case, num.

Everything after the colon (:) specifies the format_spec.

.3 sets the precision to 3.

g removes insignificant zeros. See
http://en.wikipedia.org/wiki/Printf#fprintf

For example:

tests=[(1.00, '1'),
       (1.2, '1.2'),
       (1.23, '1.23'),
       (1.234, '1.23'),
       (1.2345, '1.23')]

for num, answer in tests:
    result = '{0:.3g}'.format(num)
    if result != answer:
        print('Error: {0} --> {1} != {2}'.format(num, result, answer))
        exit()
    else:
        print('{0} --> {1}'.format(num,result))

yields

1.0 --> 1
1.2 --> 1.2
1.23 --> 1.23
1.234 --> 1.23
1.2345 --> 1.23

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Using Python 3.6 or newer, you could use f-strings:

In [40]: num = 1.234; f'{num:.3g}'
Out[40]: '1.23'