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Home/ Questions/Q 7799239
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T00:14:40+00:00 2026-06-02T00:14:40+00:00

What is an efficient way to multliply two numpy arrays together? For example, given

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What is an efficient way to multliply two numpy arrays together? For example, given

A = [1, 2, 3, 4]
B = [2, 3, 5, 7]

I want to calculate the dot product between A and B, which is

  A.B/|A||B| = (1*2 + 2*3 + .. 4*7)/sqrt(1^2 + 2^2... +4^2) * sqrt(.....)

How can I do this efficiently and fast?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T00:14:42+00:00Added an answer on June 2, 2026 at 12:14 am

    If you are using numpy, numpy.dot would do the Job for you

    numpy.dot(A,B)
    51
    

    The Fastest norm for a vector would be

    n = math.sqrt(numpy.dot(A,A.conj()))
    

    and here is the comparison with other methods

    >>> t1=timeit.Timer("n = math.sqrt(numpy.dot(A,A.conj()))","from __main__ import A,math,numpy")
    >>> t2=timeit.Timer("n = math.sqrt(sum(abs(A)**2))","from __main__ import A,math")
    >>> t3=timeit.Timer("numpy.linalg.norm(A)","from __main__ import A,numpy")
    >>> print "%.2f usec/pass" % (1000000 * t1.timeit(number=100000)/100000)
    2.82 usec/pass
    >>> print "%.2f usec/pass" % (1000000 * t2.timeit(number=100000)/100000)
    13.16 usec/pass
    >>> print "%.2f usec/pass" % (1000000 * t3.timeit(number=100000)/100000)
    15.68 usec/pass
    >>> 
    
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