Question

What is following will surely appear very simple for c coders but I am coding a small program to modelize some game called gomoku. For the user, you have to enter an integer N wich corresponds to a ‘N times N’ square which consists of ‘N times N’ integers.

So the code is runnig quite well but I have some simple question : when I enter the ‘N times N’ integers, I made some

    int N;
    scanf("%d",&N);
    char c[N][N];
    while (i<N){
        scanf("%s\n",&c[i]); 
        i++;
    }

then I converted the char to int for each c[i] to make some computation involving c[i][j], which is quite unnatural. But if I had to declare int c[N][N], it would be impossible to retrive the same integers c[i][j] like those I inputed when the while-loop is running.

Does anyone has an idea to declare int c[N][N], inputing integers, and then computing the same when computing with integers c[i][j] ?

Best,
Newben

Answer 1

You don’t have to read char and then convert it to int. You can just simply read integeres:

for(int i = 0; i < N; ++i)
    scanf("%d", &c[i]);       //of course c has to be int** type

And are you sure that you want to read just N integers? Not NN for whole array? In case you want to read NN objects to array, code should look like this:

int N, i, j;
scanf("%d",&N);
int c[N][N];

for(i = 0; i < N; ++i)
{
    for(j = 0; j < N; ++j)
    {
        scanf("%d", &c[i][j]);
        /* do something */
    }
}