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Asked: May 10, 20262026-05-10T20:30:25+00:00 2026-05-10T20:30:25+00:00

What is the concept of erasure in generics in Java?

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What is the concept of erasure in generics in Java?

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  1. 2026-05-10T20:30:26+00:00Added an answer on May 10, 2026 at 8:30 pm

    It’s basically the way that generics are implemented in Java via compiler trickery. The compiled generic code actually just uses java.lang.Object wherever you talk about T (or some other type parameter) – and there’s some metadata to tell the compiler that it really is a generic type.

    When you compile some code against a generic type or method, the compiler works out what you really mean (i.e. what the type argument for T is) and verifies at compile time that you’re doing the right thing, but the emitted code again just talks in terms of java.lang.Object – the compiler generates extra casts where necessary. At execution time, a List<String> and a List<Date> are exactly the same; the extra type information has been erased by the compiler.

    Compare this with, say, C#, where the information is retained at execution time, allowing code to contain expressions such as typeof(T) which is the equivalent to T.class – except that the latter is invalid. (There are further differences between .NET generics and Java generics, mind you.) Type erasure is the source of many of the ‘odd’ warning/error messages when dealing with Java generics.

    Other resources:

    • Oracle documentation
    • Wikipedia
    • Gilad Bracha’s Java generics guide (PDF – highly recommended; link may need to change periodically)
    • Angelika Langer’s Java Generics FAQ
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