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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:08:11+00:00 2026-05-13T08:08:11+00:00

What is the difference between using Function.prototype.apply() and Function.prototype.call() to invoke a function? const

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What is the difference between using Function.prototype.apply() and Function.prototype.call() to invoke a function?

const func = function() {
    alert("Hello world!");
};

func.apply() vs. func.call()

Are there performance differences between the two aforementioned methods? When is it best to use call over apply and vice versa?

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:08:12+00:00Added an answer on May 13, 2026 at 8:08 am

    The difference is that apply lets you invoke the function with arguments as an array; call requires the parameters be listed explicitly. A useful mnemonic is "A for array and C for comma."

    See MDN’s documentation on apply and call.

    Pseudo syntax:

    theFunction.apply(valueForThis, arrayOfArgs)

    theFunction.call(valueForThis, arg1, arg2, ...)

    There is also, as of ES6, the possibility to spread the array for use with the call function, you can see the compatibilities here.

    Sample code:

    function theFunction(name, profession) {
        console.log("My name is " + name + " and I am a " + profession +".");
    }
    theFunction("John", "fireman");
    theFunction.apply(undefined, ["Susan", "school teacher"]);
    theFunction.call(undefined, "Claude", "mathematician");
    theFunction.call(undefined, ...["Matthew", "physicist"]); // used with the spread operator
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