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Home/ Questions/Q 6943253
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:07:53+00:00 2026-05-27T13:07:53+00:00

What is the diffrence beatween say: Vector<int*> myVector[5] and Vector<int> *myVector[5] The way I

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What is the diffrence beatween say:

Vector<int*> myVector[5] and Vector<int> *myVector[5]

The way I see it, in the first case, my vector will contain 5 counts of pointers to ints.
In the second case, myVector is a pointer to an array of 5 ints.

The reason I ask is because I wrote some code a while back and now I don’t understand it any more.

With Vector<int> *myVector[5], why can I do

for(int i = 0; i < 5; i++)
        {
            myVector[i] = new Integer(13);
        }

I know for a fact that the operator new returns a pointer, and then I’m storing it in myVector, but a pointer to an int is not an int right?
I’m confused.

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:07:54+00:00Added an answer on May 27, 2026 at 1:07 pm
    Vector<int*> myVector[5]
    

    Creates an array of size 5 to Vector<int*>.

     Vector<int> *myVector[5]
    

    Creates an array of 5 pointers to Vector<int>.
    Instead, Using vector to vector is a cleaner soution:

    vector<vector<int> > myVector(5);
    
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