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Asked: May 10, 20262026-05-10T20:25:13+00:00 2026-05-10T20:25:13+00:00

What is the idiomatic Python equivalent of this C/C++ code? void foo() { static

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What is the idiomatic Python equivalent of this C/C++ code?

void foo() {     static int counter = 0;     counter++;     printf('counter is %d\n', counter); } 

specifically, how does one implement the static member at the function level, as opposed to the class level? And does placing the function into a class change anything?

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  1. 2026-05-10T20:25:13+00:00Added an answer on May 10, 2026 at 8:25 pm

    A bit reversed, but this should work:

    def foo():     foo.counter += 1     print 'Counter is %d' % foo.counter foo.counter = 0 

    If you want the counter initialization code at the top instead of the bottom, you can create a decorator:

    def static_vars(**kwargs):     def decorate(func):         for k in kwargs:             setattr(func, k, kwargs[k])         return func     return decorate 

    Then use the code like this:

    @static_vars(counter=0) def foo():     foo.counter += 1     print 'Counter is %d' % foo.counter 

    It’ll still require you to use the foo. prefix, unfortunately.

    (Credit: @ony)

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