What is the meaning of using the second parameter with a comma in the below code?
int *num = new int[25,2];
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That’s the comma operator in action: it evaluates it’s operand and returns the last one, in your case 2.
So that is equivalent with:
It’s probably safe to say that the
25,2part was not what was intended, unless it’s a trick question.Edit: thank you Didier Trosset.