Question

What is the most efficient (fastest) way to get a lower bound of zero?

Math.max(0, x) will work, returning 0 for any negative value of x. However, my experience with Math.* is that there often is a far more performant trick to do it faster. Anyone know of any in this case?

Bitwise tricks are fine; I always like finding real uses for those operators. Anything that will return false, if x is negative, also is fine.

Edit
To clarify, if x is greater than 0, I want that value. So I can’t just do x < 0, as that will only give me true, not x.

Answer 1

One way with your requirements is:

x > 0 && x

given that you are ok with the expression evaluating to false when x is 0 or negative. If you just want false when x is negative, you can do:

x >= 0 && x

Examples:

3 > 0 && 3;     // result: 3
-1 > 0 && -1;   // result: false
0 > 0 && 0;     // result: false

0 >= 0 && 0;    // result: 0