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Asked: May 10, 20262026-05-10T17:03:01+00:00 2026-05-10T17:03:01+00:00

What is the most efficient way to get the default constructor (i.e. instance constructor

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What is the most efficient way to get the default constructor (i.e. instance constructor with no parameters) of a System.Type?

I was thinking something along the lines of the code below but it seems like there should be a simplier more efficient way to do it.

Type type = typeof(FooBar) BindingFlags flags = BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.Instance; type.GetConstructors(flags)     .Where(constructor => constructor.GetParameters().Length == 0)     .First(); 
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  1. 2026-05-10T17:03:02+00:00Added an answer on May 10, 2026 at 5:03 pm
    type.GetConstructor(Type.EmptyTypes) 
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