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Home/ Questions/Q 7558277
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T12:19:47+00:00 2026-05-30T12:19:47+00:00

What is the most efficient way to search a list of objects and also

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What is the most efficient way to search a list of objects and also increment one of its variables? Also addData() function call 10000 time and in this list have max 30 diff-diff key with increment variable .

Thanks,

public void addData(List<DataWise> wise ,String name) 
    {
        if(wise!=null)
        {

            for (DataWise dataWise : wise) {

                if(dataWise.getName().equals(name))
                {
                    dataWise.setVisits(1);
                    return;
                }
            }
        }
        DataWise dataWise2=new DataWise(name,1);
        wise.add(dataWise2);
    }

public class DataWise 
{

    private String name;
    private int visits;

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public int getVisits() {
        return visits;
    }
    public void setVisits(int visits) {
        this.visits+= visits;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-30T12:19:49+00:00Added an answer on May 30, 2026 at 12:19 pm

    If it’s guarantteed that the name of each DataWise is unique in the list, use a HashMap<String, DataWise>, where the String key is the name of the DataWise. This will lead to O(1) instead of O(n):

    Map<String, DataWise> map = new HashMap<String, DataWise>();
    ...
    DataWise wise = map.get(name);
    if (wise != null) {
        wise.incrementVisits();
    }
    else {
        wise = new DataWise(name, 1);
        map.put(name, wise);
    }
    

    Note that a setter (setVisits()) should set the visits value to the value of the argument. Incrementing the number of visits is really counter-intuitive. This is why I used an incrementVisits method, which is much clearer.

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