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Home/ Questions/Q 967349
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:18:03+00:00 2026-05-16T02:18:03+00:00

What is the proper way to implement a getter method for a lazily-initialized member

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What is the proper way to implement a getter method for a lazily-initialized member variable and maintain const-correctness? That is, I would like to have my getter method be const, because after the first time it is used, it’s a normal getter method. It is only the first time (when the object is first initialized) that const does not apply. What I would like to do:

class MyClass {
  MyClass() : expensive_object_(NULL) {}
  QObject* GetExpensiveObject() const {
    if (!expensive_object_) {
      expensive_object = CreateExpensiveObject();
    }
    return expensive_object_;
  }
private:
  QObject *expensive_object_;
};

Can I eat my cake and have it too?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:18:04+00:00Added an answer on May 16, 2026 at 2:18 am

    I propose encapsulating James Curran‘s answer into a class of its own if you do this frequently:

    template <typename T>
    class suspension{
       std::tr1::function<T()> initializer;
       mutable T value;
       mutable bool initialized;
    public:
       suspension(std::tr1::function<T()> init):
          initializer(init),initialized(false){}
       operator T const &() const{
          return get();
       }
       T const & get() const{
          if (!initialized){
             value=initializer();
             initialized=true;
          }
          return value;
       }
    };
    

    Now use this in your code as follows:

    class MyClass {
      MyClass() : expensive_object_(CreateExpensiveObject) {}
      QObject* GetExpensiveObject() const {
        return expensive_object_.get();
      }
    private:
      suspension<QObject *> expensive_object_;
    };
    
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