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Home/ Questions/Q 8609177
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:48:59+00:00 2026-06-12T03:48:59+00:00

What is the proper way to initialize java enum based singleton, if I have

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What is the proper way to initialize java enum based singleton, if I have to initialize it before I can use the object.

I have started writing the code , but I am not sure if I am doing it right. Could you help me to implement this singleton correct for me?

public enum BitCheck {

    INSTANCE;

    private static HashMap<String, String> props = null;

    public synchronized void  initialize(HashMap<String, String> properties) {
        if(props == null) {
            props = properties;
        }
    }

    public boolean isAenabled(){
        return "Y".equalsIgnoreCase(props.get("A_ENABLED"));
    }

    public boolean isBenabled(){
        return "Y".equalsIgnoreCase(props.get("B_ENABLED"));
    }

}
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  1. Editorial Team
    Editorial Team
    2026-06-12T03:49:00+00:00Added an answer on June 12, 2026 at 3:49 am

    It’s perfectly possible to create constructor for enum:

    public enum BitCheck {
    
        INSTANCE;
    
        BitCheck() {
            props = new HashMap<String, String>();
        }
    
        private final Map<String, String> props;
    
        //..
    
    }
    

    Note that:

    • props field can be final (we like final)
    • props doesn’t have to be static
    • constructor is called automatically and eagerly for you

    Pay attention to the last point. Since enum-singletons are created eagerly when the enum BitCheck class is loaded, you have no way to pass any arguments to the constructor. Of course you can through INSTANCE declaration:

    public enum BitCheck {
    
        INSTANCE(new HashMap<String, String>());
    
        BitCheck(final Map<String, String> props) {
            this.props = props;
        }
    

    but this doesn’t make any difference, right? What do you want to achieve? Maybe you actually need lazy-initialized singleton?

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