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What is the regular expression for . and .. ?
if(key.matches(".")) {
do something
}
The matches accepts String which asks for regular expression. Now i need to remove all DOT’s inside my MAP.
. matches any character so needs escaping i.e.
\., or\\.within a Java string (because\itself has special meaning within Java strings.)You can then use
\.\.or\.{2}to match exactly 2 dots.