Question

What is wrong in this code
if(getResponseDataMap().containsKey("A"){
a.setText(getResponseDataMap().get("A").toString);
}

Converted like this .

getResponseDataMap().containsKey("A")?a.setText(getResponseDataMap().get("A").toString()):""

where getLocalRequestDataMap is a HashMap . And setText is function of android

It give compile time error
Multiple markers at this line
– Type mismatch: cannot convert from String to
boolean
– Syntax error, insert “)” to complete Expression
– Syntax error on token “)”, delete this token

Answer 1

Just on its own, the problem is that you’ve given an expression which isn’t a statement.

With an assignment, however, it’s fine:

import java.util.*;

public class Test {
    public static void main(String[] args) {
        HashMap<String, String> map = new HashMap<String, String>();

        String x = map.containsKey("A") ? "" : "";
    }
}

I suspect the problem is in some code you haven’t shown. Please give more context – ideally a short but complete program like mine, but which demonstrates the error.

EDIT: Now that you’ve edited the question, you’ll probably get a different error. The conditional operator isn’t a valid stand-alone statement, and each of the operands needs to be a non-void expression (with some other caveats as well). So instead of this:

getResponseDataMap().containsKey("A") ?
    a.setText(getResponseDataMap().get("A").toString()):""

I suspect you want:

a.setText(getResponseDataMap().containsKey("A") ? 
          getResponseDataMap().get("A").toString() : null);

However, I would personally write this as:

Object response = getResponseDataMap().get("A");
a.setText(response == null ? "" : response.toString());

On the other hand, if you only want to set the text when the map contains the key, then you should go back to your original if statement, or possibly:

Object response = getResponseDataMap().get("A");
if (response != null) {
    a.setText(response.toString());
}