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Home/ Questions/Q 6078491
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:50:23+00:00 2026-05-23T10:50:23+00:00

what is wrong why is that the richtextbox doesnt get the stream of Process

  • 0

what is wrong why is that the richtextbox doesnt get the stream of Process output? theres no text display in richtextbox..

 private void button1_Click(object sender, EventArgs e)
    {

        Process sortProcess;
        sortProcess = new Process();
        sortProcess.StartInfo.FileName = "sort.exe";
        sortProcess.StartInfo.Arguments = this.comboBox1.SelectedItem.ToString();
        // Set UseShellExecute to false for redirection.
        sortProcess.StartInfo.CreateNoWindow = true;
        sortProcess.StartInfo.UseShellExecute = false;



        // Redirect the standard output of the sort command.  
        // This stream is read asynchronously using an event handler.
        sortProcess.StartInfo.RedirectStandardOutput = true;
        sortOutput = new StringBuilder("");

        // Set our event handler to asynchronously read the sort output.
        sortProcess.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);

        // Redirect standard input as well.  This stream
        // is used synchronously.
        sortProcess.StartInfo.RedirectStandardInput = true;

        // Start the process.
        sortProcess.Start();



        // Start the asynchronous read of the sort output stream.
        sortProcess.BeginOutputReadLine();
        sortProcess.WaitForExit();


        richTextBox1.AppendText(sortOutput.ToString());
    }

    private static void SortOutputHandler(object sendingProcess,
        DataReceivedEventArgs outLine)
    {
            sortOutput.Append(Environment.NewLine +
                "[" + numOutputLines.ToString() + "] - " + outLine.Data);
        }
    }

so when sort.exe launches, it displays text, i want all those text be displayed also in richtextbox in RealTime (i dont want to wait for the process to exit, and then read all output)

how can i do it? any wrong part of my code? thanks

UPDATE @botz

i added this in my code

 private void SortOutputHandler(object sendingProcess,
        DataReceivedEventArgs outLine)
    {

            sortOutput.Append(Environment.NewLine +
                "[" + numOutputLines.ToString() + "] - " + outLine.Data);
            richTextBox1.AppendText(sortOutput.ToString());


    }

but it throws this exception

Cross-thread operation not valid: Control 'richTextBox1' accessed from a thread other than the thread it was created on.
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:50:24+00:00Added an answer on May 23, 2026 at 10:50 am

    WaitForExit() blocks your UI Thread, so you don’t see the new output.
    Either wait for the process in a separate thread or replace WaitForExit() with something like this:

    while (!sortProcess.HasExited) {
         Application.DoEvents(); // This keeps your form responsive by processing events
    }
    

    In your SortOutputHandler, you can now directly append output to your textbox. But you should remember to check if you need to invoke it on the UI Thread.

    You can check if it’s on the UI thread this way in your handler:

        if (richTextBox1.InvokeRequired) { richTextBox1.BeginInvoke(new DataReceivedEventHandler(SortOutputHandler), new[] { sendingProcess, outLine }); }
        else {
            sortOutput.Append(Environment.NewLine + "[" + numOutputLines.ToString() + "] - " + outLine.Data);
            richTextBox1.AppendText(sortOutput.ToString());
        }
    
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