Question

What is wrong with my code? I want to print out the array, but when I try to do so it seems to print out an address instead.

#include <iostream>
#include <ctime>
#include <stdlib.h>

using namespace std;

int main ()
{
    srand(time(NULL));

    int array[9]= {0};

    for (int i=0;i<=8;i++)
    {
        array[i]= (rand()%101);
    }

    cout<< array;

    system ("PAUSE");
    return 0;
}

Answer 1

You can’t just cout an array. Arrays are not cout-able. Whenever you successfully cout something of type T, it means that there’s a dedicated overloaded << operator designed specifically to cout values of type T. And there’s no dedicated << operator for cout-ing arrays (aside from strings). For this reason the compiler chooses the closest match for the given argument type: a << operator for pointers. Since arrays are convertible to pointers, that << is applicable here.

If you want to cout the values of all elements of your array, you’ll have to either cout them manually, one by one, or use some standard algorithm that can do it for you. For example

std::copy(array, array + 9, std::ostream_iterator<int>(std::cout, " "));