Question

What is wrong with my code? why the images not shown? i need to assign that method at the asp:image ? if yes – how ?

public int bla()
{
    SqlConnection connection = new SqlConnection("Data Source=tcp:**.****;Initial Catalog=*****;User ID=****;Password=****;Integrated Security=False;");
    string commandtext = "SELECT Minbuy FROM items";
    SqlCommand command = new SqlCommand(commandtext, connection);
    connection.Open();
    int itemsMin = (int)command.ExecuteScalar();

    string commandtext2 = "SELECT purchaseid FROM purchase";
    SqlCommand command2 = new SqlCommand(commandtext2, connection);
    int purchase = (int)command2.ExecuteScalar();

    if (itemsMin >= purchase)
        image3.Visible = true;
    else
        image4.Visible = true;

    connection.Close();



    return itemsMin;




}

the images at the aspx file:

     <asp:Image ID="image3"  runat="server" Visible="false" ImageUrl="~/images/V.png" />

     <asp:Image ID="image4"  runat="server" Visible="false" ImageUrl="~/images/X.png" />

Answer 1

It’s pretty hard to say without knowing what the data is!

A wild guess would be that an exception is thrown before the line if (itemsMin >= purchase).

My first step would be to log the output of each sql statement, and also add logging if an exception is thrown in a try catch finally block.

For example:

    public int bla()
    {
        int itemsMin = -1;
        try
        {
            SqlConnection connection = new SqlConnection("Data Source=tcp:**.****;Initial Catalog=*****;User ID=****;Password=****;Integrated Security=False;");
            string commandtext = "SELECT Minbuy FROM items";
            SqlCommand command = new SqlCommand(commandtext, connection);
            connection.Open();
            itemsMin = (int)command.ExecuteScalar();

            string commandtext2 = "SELECT purchaseid FROM purchase";
            SqlCommand command2 = new SqlCommand(commandtext2, connection);
            int purchase = (int)command2.ExecuteScalar();

            if (itemsMin >= purchase)
                image3.Visible = true;
            else
                image4.Visible = true;

            connection.Close();
        }
        catch (System.Exception ex)
        {
            System.Diagnostics.Trace.WriteLine(ex);
        }
        return itemsMin;
    }