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Home/ Questions/Q 804563
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:56:24+00:00 2026-05-14T23:56:24+00:00

What is wrong with this code? var divarray = []; var articleHTML = [];

  • 0

What is wrong with this code?

var divarray = [];
var articleHTML = [];
var absHTML;
var keyHTML;
var bodyHTML = [];
var i = 0;
divarray = document.getElementById("yui-main").getElementsByTagName("div");
for ( var j in divarray) {
    if(divarray[i].className == "articleBody"){
        articleHTML = divarray[i];
        for( var k in articleHTML ){
            bodyHTML[i] = '';
            if(articleHTML[i].className == "issueMiniFeature"){continue;}
            if(articleHTML[i].className == "abstract"){absHTML = articleHTML[i]; continue;}
            if(articleHTML[i].className == "journalKeywords"){keyHTML = articleHTML[i]; continue;}
            bodyHTML[i] = articleHTML[i];
        }
        break;
    }
    i++;
}

The error I get is:

TypeError: Cannot read property 'className' of undefined

I am using Google Chrome.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T23:56:25+00:00Added an answer on May 14, 2026 at 11:56 pm

    You’re using a very strange loop.

     for (var j in array) {
        // use array[i]
        ++ i
     }
    

    The problem is .getElementsByTagName doesn’t return an array, but an array-like interface. For example:

    >>> for (var j in document.getElementsByTagName('body')) console.log(j)
    0
    length
    item
    namedItem
    

    Therefore, in your for/in loop, i will go up to array.length + 2 instead of array.length - 1. Since array[array.length + 2] does not exist, it will return undefined and throw the error when you try to access a property of it.


    Just always use

    for (var i = 0, len = array.length; i < len; ++ i) {
      ...
    }
    

    with arrays.

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