What will b return ?
byte b = (byte)0x8A;
System.out.println("Value"+b);
What will it print? And when does the value will return a negation?
What will b return ? byte b = (byte)0x8A; System.out.println(Value+b); What will it print?
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What will b return ?
byte b = (byte)0x8A;
System.out.println("Value"+b);
What will it print? And when does the value will return a negation?
Probably not what you expect. In Java a
byteis a (signed) number not a character, so when0x8Ais converted to a String you will get the decimal representation of a small negative number.So I’d expect:
If you wanted
0x8Ato be interpreted as a character you should write this:But that doesn’t really work either because the Unicode codepoint 008A is not a printing character. (And for what it is worth, 0x8A is not ASCII because true ASCII is a 7 bit character set.)