Question

What would be the best logic to check all the letters in a given string.

If all the 26 letters are available in the provided string, I want to check that and perform so ops. eg. Pack my box with five dozen liquor jugs.

1. Would using a Hash be useful?
2. Or using a bit map? or any other way?

BTW my code would be in Java.

Answer 1

Not yet fully optimized:

public static void main(String... a) {
    String s = "Pack my box with five dozen liquor jugs.";
    int i=0;
    for(char c : s.toCharArray()) {
        int x = Character.toUpperCase(c);
        if (x >= 'A' && x <= 'Z') {
            i |= 1 << (x - 'A');
        }
    }
    if (i == (i | ((1 << (1 + 'Z' - 'A')) - 1))) {
        System.out.println("ok");
    }
}