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Home/ Questions/Q 1076357
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:24:28+00:00 2026-05-16T21:24:28+00:00

What would be the best way to get the latest inserted object using AppEngine

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What would be the best way to get the latest inserted object using AppEngine ?
I know in Django this can be done using

MyObject.objects.latest()

in AppEngine I’d like to be able to do this

class MyObject(db.Model):
  time = db.DateTimeProperty(auto_now_add=True)

# Return latest entry from MyObject.
MyObject.all().latest()

Any idea ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:24:29+00:00Added an answer on May 16, 2026 at 9:24 pm

    Your best bet will be to implement a latest() classmethod directly on MyObject and call it like

    latest = MyObject.latest()
    

    Anything else would require monkeypatching the built-in Query class.

    Update

    I thought I’d see how ugly it would be to implement this functionality. Here’s a mixin class you can use if you really want to be able to call MyObject.all().latest():

    class LatestMixin(object):
        """A mixin for db.Model objects that will add a `latest` method to the
        `Query` object returned by cls.all(). Requires that the ORDER_FIELD
        contain the name of the field by which to order the query to determine the
        latest object."""
    
        # What field do we order by?
        ORDER_FIELD = None
    
        @classmethod
        def all(cls):
            # Get the real query
            q = super(LatestMixin, cls).all()
            # Define our custom latest method
            def latest():
                if cls.ORDER_FIELD is None:
                    raise ValueError('ORDER_FIELD must be defined')
                return q.order('-' + cls.ORDER_FIELD).get()
            # Attach it to the query
            q.latest = latest
            return q
    
    # How to use it
    class Foo(LatestMixin, db.Model):
        ORDER_FIELD = 'timestamp'
        timestamp = db.DateTimeProperty(auto_now_add=True)
    
    latest = Foo.all().latest()
    
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