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Home/ Questions/Q 7973971
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T08:14:57+00:00 2026-06-04T08:14:57+00:00

What would be the difference between matching like: fun(Binary) -> [Value, Rest] = binary:split(Binary,

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What would be the difference between matching like:

fun(Binary) ->
    [Value, Rest] = binary:split(Binary, <<101>>)
end

and

fun(Binary) ->
    [Value, <<Rest/binary>>] = binary:split(Binary, <<101>>)
end

I am thinking that one may simply increment a counter as it traverses the binary and keep the sub binary pointer and the other will copy a new binary. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-04T08:14:57+00:00Added an answer on June 4, 2026 at 8:14 am

    I can think of pattern matching in two ways.

    Method 1:

    [A,B] = [<<"abcd">>,<<"fghi">>] 
    

    Method 2:

    [A, <<B/binary>>] = [<<"abcd">>,<<"fghi">>]
    

    Unless you need to make it sure B is binary, Method 2 will take it longer, few micro seconds, because it’s not just assigning <<“fghi”>> to B, but also make it sure it is bianary.

    However if you need more parsing than method 2, you can go further, which method 1 can’t do.

    [A, <<B:8, Rest/binary>>] = [<<"abcd">>,<<"fghi">>].
    
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