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Home/ Questions/Q 6105173
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:55:37+00:00 2026-05-23T13:55:37+00:00

What would be the most elegant way to process the first IEnumerable item differently

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What would be the most elegant way to process the first IEnumerable item differently than others, without having to test on each iteration?

With a test on each iteration, it would look like this:

// "first item done" flag
bool firstDone = false;

// items is an IEnumerable<something>
foreach (var item in items)
{
    if (!firstDone)
    {
        // do this only once
        ProcessDifferently(item);
        firstDone = true;
        continue;
    }

    ProcessNormally(item);
}

If I do this:

ProcessDifferently(items.First());
ProcessNormally(items.Skip(1)); // this calls `items.GetEnumerator` again

it will invoke GetEnumerator twice, which I would like to avoid (for Linq-to-Sql cases, for example).

How would you do it, if you need to do several times around your code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:55:38+00:00Added an answer on May 23, 2026 at 1:55 pm

    If I needed to do it in several places, I’d extract a method:

    public void Process<T>(IEnumerable<T> source,
                           Action<T> firstAction,
                           Action<T> remainderAction)
    {
        // TODO: Argument validation
        using (var iterator = source.GetEnumerator())
        {
            if (iterator.MoveNext())
            {
                firstAction(iterator.Current);
            }
            while (iterator.MoveNext())
            {
                remainderAction(iterator.Current);
            }
        }
    }
    

    Called as:

    Process(items, ProcessDifferently, ProcessNormally);
    

    There are other options too, but it would really depend on the situation.

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