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Home/ Questions/Q 6386739
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T03:03:50+00:00 2026-05-25T03:03:50+00:00

What wrong with this code (or my sanity for that matter :D ). The

  • 0

What wrong with this code (or my sanity for that matter 😀 ).

The Distinct clause in the Select statement is NOT working. It’s result set contains All rows for Each EmpID in ej. Please help!!

Declare @SurveyID int;
SET @SurveyID = 2;

IF OBJECT_ID('tempdb..#t') IS NOT NULL     DROP TABLE #t 
IF OBJECT_ID('tempdb..#t') IS NOT NULL     DROP TABLE #t1 


SELECT  Distinct(ej.EmpID),
        ej.JobCode,
        ej.SurveyID,
        ej.IsCompleted,
        Coalesce(ej.Declined,0) AS Declined,
        emp.Company,
        emp.UserID,
        emp.LoginRecord,
        count(JobCode) AS Benchmark
    into #t
    FROM SAS.EmployerJobs ej
        INNER JOIN SAS.Employer emp
            ON ej.EmpID = emp.EmpID
    Where (ej.SurveyID = @SurveyID)
    GROUP BY ej.EmpID, ej.JobCode, ej.SurveyID, ej.IsCompleted, Declined, emp.Company, emp.UserID, emp.LoginRecord
    Order by ej.EmpID ASC

Select * from #t

drop table #t
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:03:50+00:00Added an answer on May 25, 2026 at 3:03 am

    If you only require one row for each distinct EmpID in the result set, then you need to decide how to aggregate the multiple rows of data (multiple jobs) for each EmpID. For example, choosing the minimum value.

    But from the names and relations, it seems that an EmpID can have multiple jobs, so it doesn’t seem to make sense to expect only one row per EmpID if you want also to list the individual jobs.

    UPDATE: To count the number of JobCodes

    SELECT  ej.EmpID,
            ej.SurveyID,
            emp.Company,
            emp.UserID,
            emp.LoginRecord,
            count(JobCode) AS Benchmark
        into #t
        FROM SAS.EmployerJobs ej
            INNER JOIN SAS.Employer emp
                ON ej.EmpID = emp.EmpID
        Where (ej.SurveyID = @SurveyID)
        GROUP BY ej.EmpID, ej.SurveyID, emp.Company, emp.UserID, emp.LoginRecord
        Order by ej.EmpID ASC
    

    Your original query attempted to pull in data that varies per job, and that is why you were not getting the aggregation. (E.g. IsCompleted, declined etc..) For aggregation to work, only include data that is an aggregate of the job data, like count(JobCode), or doesn’t vary per job, such as employer attributes.

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