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Home/ Questions/Q 6726589
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:56:41+00:00 2026-05-26T09:56:41+00:00

What’s the best alternative to BOOST_FOREACH when you want to iterate over std::set? When

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What’s the best alternative to BOOST_FOREACH when you want to iterate over std::set?

When I try and do what seems to be a reasonable method for iterating over a set I get compile errors. This code:

set<string> nameSet;
string aName;
BOOST_FOREACH(nameSet, aName) {
  cout << aName << endl;
}

generates this compile error with gcc 4.4.3:

error: no match for ‘operator=’ in ‘nameSet = boost::foreach_detail_::deref [with T = std::basic_string<char, std::char_traits<char>, std::allocator<char> >, C = mpl_::bool_<false>](((const boost::foreach_detail_::auto_any_base&)((const boost::foreach_detail_::auto_any_base*)_foreach_cur70)), 0u)’

According to this link the two aren’t compatible because std::set::iterator must allow mutation of the value it refers to.

I can think of a few ham fisted methods, but am wondering if there is a cleaner way to iterate over the set.

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:56:42+00:00Added an answer on May 26, 2026 at 9:56 am

    Works for me. Maybe you have the parameters to BOOST_FOREACH reversed.

    #include <set>
    #include <string>
    #include <iostream>
    #include <boost/foreach.hpp>
    
    int main(int ac, char **av) {
    
      std::set<std::string> nameSet(av+1, av+ac);
    
      BOOST_FOREACH(const std::string& aName, nameSet) {
        std::cout << aName << "\n";
      }
    
      BOOST_FOREACH(std::string aName, nameSet) {
        std::cout << aName << "\n";
      }
    
      std::string aName;
      BOOST_FOREACH(aName, nameSet) {
        std::cout << aName << "\n";
      }
    }
    

    According to this link the two aren’t compatible because std::set::iterator must allow mutation of the value it refers to.

    That’s not really what that link says. What you cannot do, and what that link says won’t work, is this:

    BOOST_FOREACH(std::string& aName, nameSet) {
    }
    

    Because you cannot form a non-const reference from a const expression. (Namely, each the const members of a std::set.)

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