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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T00:29:48+00:00 2026-05-12T00:29:48+00:00

What’s the best way to implement keywords as optional flags to a function? I

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What’s the best way to implement keywords as optional flags to a function?
I want to make function calls such as:

(myfunction 5)
(myfunction 6 :do-this)
(myfunction 3 :go-here)
(myfunction 2 :do-this :do-that)

Using defn, I can define a function such as:

(defn myfunction [value & flags] ... )

But the flags becomes a list. I can write my own function to search the list, but such a function isn’t included in the core library, so I assume it’s not idiomatic.

What I’m using now:

(defn flag-set? [list flag] (not (empty? (filter #(= flag %) list))))
(defn flag-add [list flag] (cons flag list))
(defn flag-remove [list flag] (filter #(not= flag %) list))
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  1. Editorial Team
    Editorial Team
    2026-05-12T00:29:48+00:00Added an answer on May 12, 2026 at 12:29 am

    Lists (as well as vectors and maps) are not a good choice of data structure for value-based lookups (will be linear time), that’s why clojure.core doesn’t have such functions.

    Sets do provide fast value-based lookups via “contains?”, so how about

    (defn foo [value & flags]
      (let [flags (set flags)]
        (if (contains? flags :add-one)
          (inc value)
          value)))
    

    If there won’t be more than one flag, you can use destructuring like this:

    (defn foo [value & [flag]] …)
    
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