Question

What’s the best way to write following if condition in Ruby?

if (    $response_code == "400" ||
        $response_code == "401" ||
        $response_code == "402" ||
        $response_code == "403" ||
        $response_code == "404" ||
        $response_code == "411" ||
        $response_code == "500" ||
        $response_code == "501" ||
        $response_code == "502" ||
        $response_code == "0")
    {
        return false;
    }

Ruby seems to have concise way of doing things so was wondering if I can avoid writing long stuff like this.

Answer 1

Possible solution:

ACCEPTED_CODES = %w[400 401 402 403 404 411 500 501 502 0]

def test(response_code)
  !ACCEPTED_CODES.include?(response_code)
end