Question

what’s the easiest way to implement a string id in jpa ?
So far what I have is

@Id
@GeneratedValue
private int id;

and what I’d like to have is something like

@Id
@GeneratedValue
private String id;

but if I use it like this, I get ‘this id generator generates long, integer, short’.

Answer 1

You can create the UUID from Java like this:

UUID.randomUUID().toString();

Or if your JPA supports it, like Hibernate does, you can use:

@Id @GeneratedValue(generator="system-uuid")
@GenericGenerator(name="system-uuid", strategy = "uuid")
private String myId;

Checkout this blogpost for details.

If you google for “JPA UUID” there are many alternatives.