Question

What’s the priority ranking of numpy bitwise operators & and | ?

if I do

a & b | c

what expression does it evaluate? a & (b | c) ? (a & b) | c ?

How about

a | b & c

I also assume NOT (~) has the highest priority?

Answer 1

Here is a technique that you can use when your internet connection is down. It is applicable to many questions that you might have. The colloquial description of the technique is “Suck it and see”.

>>> from itertools import product
>>> list(product(range(2), repeat=3))
[(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]
>>> all((a & b | c) == ((a & b) | c) for a, b, c in product(range(2), repeat=3))
True
>>> all((a & b | c) == (a & (b | c)) for a, b, c in product(range(2), repeat=3))
False