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Home/ Questions/Q 7655641
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T12:33:52+00:00 2026-05-31T12:33:52+00:00

What’s the proper way to force an RSpec test to fail? I’m considering 1.should

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What’s the proper way to force an RSpec test to fail?

I’m considering 1.should == 2 however there’s probably something better.

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  1. Editorial Team
    Editorial Team
    2026-05-31T12:33:54+00:00Added an answer on May 31, 2026 at 12:33 pm

    fail/raise will do the trick (they are aliases of each other).

    Example

    specify "this test fails" do
      raise "this is my failure message"
    end
    

    Fails with:

    1) failing this test fails
       Failure/Error: raise "this is my failure message"
    
       RuntimeError:
         this is my failure message
    

    Alternatives

    If you are thinking of using raise/fail in a spec, you should consider that there are probably more explicit ways of writing your expectation.

    Additionally, raise/fail doesn’t play well with aggregate_failures because the exception short-circuits the block and won’t run any following matchers.

    Mark a test as pending

    If you need to mark a test as pending to make sure you get back to it, you could use the fail/raise, but you can also use pending.

    #  Instead of this:
    it "should do something" do
       # ...
       raise "this needs to be implemented"
    end
    
    # ✅ Try this:
    it "should do something" do
      pending "this needs to be implemented"
    end
    

    Assert that a block is not called

    If you need to ensure a block is not being executed, consider using the yield matchers. For example:

    describe "Enumerable#any?" do
      #  Instead of this:
      it "doesn't yield to the block if the collection is empty" do
        [].any? { raise "it should not call this block" }
      end
    
      # ✅ Try this:
      it "doesn't yield to the block if the collection is empty" do
        expect { |b| [].any?(&b) }.not_to yield_control
      end
    end
    
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