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Home/ Questions/Q 3635538
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T00:55:00+00:00 2026-05-19T00:55:00+00:00

What’s the Scala recipe for reading line by line from the standard input ?

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What’s the Scala recipe for reading line by line from the standard input ? Something like the equivalent java code :

import java.util.Scanner; 

public class ScannerTest {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()){
            System.out.println(sc.nextLine());
        }
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T00:55:00+00:00Added an answer on May 19, 2026 at 12:55 am

    The most straight-forward looking approach will just use readLine() which is part of Predef. however that is rather ugly as you need to check for eventual null value:

    object ScannerTest {
      def main(args: Array[String]) {
        var ok = true
        while (ok) {
          val ln = readLine()
          ok = ln != null
          if (ok) println(ln)
        }
      }
    }
    

    this is so verbose, you’d rather use java.util.Scanner instead.

    I think a more pretty approach will use scala.io.Source:

    object ScannerTest {
      def main(args: Array[String]) {
        for (ln <- io.Source.stdin.getLines) println(ln)
      }
    }
    
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