Question

Whats wrong with this?

for i in {0..16};do 
awk '/foo/ {while (getline > 0); print $0}' ${array[$i]} >> lines.txt;done

I thought “The expression “getline > 0″ will be true as long as getline successfully reads an input line. When it gets to the end-of-file, getline returns 0 and the loop is exited.”

I want to print out every line after the one containing “foo”. I get something similar to what I want with the lines above but its not correct.

Answer 1

Take out the semicolon.

awk '/foo/ { while(getline > 0) { print }}'

Or

awk 'p; /foo/{p=1}'