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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:27:02+00:00 2026-05-11T19:27:02+00:00

What’s wrong with this query: SELECT co.*, mod.COUNT(*) as moduleCount, vid.COUNT(*) as vidCount FROM

  • 0

What’s wrong with this query:

SELECT co.*, mod.COUNT(*) as moduleCount, vid.COUNT(*) as vidCount 
 FROM courses as co, modules as mod, videos as vid 
 WHERE mod.course_id=co.id AND vid.course_id=co.id ORDER BY co.id DESC

In other words, how can I do it so with every record returned from ‘courses’, there’s
an additional column called ‘modCount’ which shows the number of records in the modules table for that course_id, and another called ‘vidCount’ which does the same thing for the videos table.

Error:

Error Number: 1064

You have an error in your SQL syntax;
check the manual that corresponds to
your MySQL server version for the
right syntax to use near ‘) as
moduleCount, vid.COUNT(
) as vidCount
FROM courses as co, ‘ at line 1

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:27:02+00:00Added an answer on May 11, 2026 at 7:27 pm

    Using subselects you can do:

    SELECT co.*, 
        (SELECT COUNT(*) FROM modules mod WHERE mod.course_id=co.id) AS moduleCount, 
        (SELECT COUNT(*) FROM videos vid WHERE vid.course_id=co.id) AS vidCount
    FROM courses AS co
    ORDER BY co.id DESC
    

    But be carefull as this is an expensive query when courses has many rows.

    EDIT:
    If your tables are quite large the following query should perform much better (in favor of being more complex to read and understand).

    SELECT co.*, 
        COALESCE(mod.moduleCount,0) AS moduleCount,
        COALESCE(vid.vidCount,0) AS vidCount
    FROM courses AS co
        LEFT JOIN (
                SELECT COUNT(*) AS moduleCount, course_id AS courseId 
                FROM modules
                GROUP BY course_id
            ) AS mod
            ON mod.courseId = co.id
        LEFT JOIN (
                SELECT COUNT(*) AS vidCount, course_id AS courseId 
                FROM videos
                GROUP BY course_id
            ) AS vid
            ON vid.courseId = co.id
    ORDER BY co.id DESC
    
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