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Home/ Questions/Q 7065427
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:57:18+00:00 2026-05-28T04:57:18+00:00

When a constructor in a superclass receives arguments, it is no longer a default

  • 0

When a constructor in a superclass receives arguments, it is no longer a default constructor, right? For example

class a {
    public:
      int a;
      int b;
      a(int c, int d){
        cout<<"hello";
      };
} 

Now when I try to make a subclass, the program causes an error, it says “no default constructor is defined in the super class”. How can I solve this problem? I know that if I remove the arguments, everything is going to be fine but I’m told not to do so in my C++ test. Please help me figure it out.

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:57:18+00:00Added an answer on May 28, 2026 at 4:57 am

    You normally deal with this with an initializer list:

    #include <iostream>
    
    class a { 
    public:
        a(int c, int d) { std::cout << c << " " << d << "\n"; }
    };
    
    class b : public a { 
    public:
        b() : a(1, 2) {}
    };
    
    int main() { 
        b x;
        return 0;
    }
    
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