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Home/ Questions/Q 636965
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:34:20+00:00 2026-05-13T20:34:20+00:00

When a form has multiple image inputs and the server side uses their names

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When a form has multiple image inputs and the server side uses their names and/or values to distinguish which one was clicked, it works perfectly in FireFox. However, people often write the whole thing before finding out that HTML specifies that nothing has to be sent, and thus some browsers are not sending it.

It’s not about sending any random object, but sending a pair as input_name=input_value. The best worst-case scenario example here would be what I’ve encountered: A list of elements all in one form and all accompanied by buttons with name="delete" value="<item_id>"

What can I do to fix this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:34:20+00:00Added an answer on May 13, 2026 at 8:34 pm

    The problem was half solved up to now: like here

    But it didn’t allow to get the value!

    The correct answer is:

    $('input[type=image]')
    .unbind('mousedown')
    .mousedown(function(){ 
      $(this).after('<input type="hidden" name="'+$(this).attr('name')+'" value="'+$(this).attr('value')+'" />'); 
    });
    

    This code creates a hidden duplicate of the input when user starts clicking it. The unbind(‘mousedown’) is to secure it happens once even if You put the code in multiple places in a weird application and it might be called more than once.

    I recommend putting it in $(document).ready();

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