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Home/ Questions/Q 8956653
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:50:07+00:00 2026-06-15T14:50:07+00:00

When a user submits a form its validated using if statements, like this if

  • 0

When a user submits a form its validated using if statements, like this

if (strlen($_POST['password']) < 5)
{
    $data['errors'][] = 'Too short';
}
elseif ($_POST['password'] != $_POST['confirm_password'])
{
    $data['errors'][] = 'doesnt match';
}

When validation is completed we check if there arent any errors

if (!$data['errors'])

And if it isnt we proceed and fill the data in to the database

However If there are errors, the USERS need to refill the whole form, I don’t want that, I need to render back some data if it’s legit

if (!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL))
{
    $data['errors'][] = 'E-mail not valid';
}

Like here, if the password validation fails but the email validation is OK, I would want to give back the email already valued in the form. Would I need to put a else statement on every validation check like } else { $data[‘postback’][’email’]; } or could I do this on another easier way?

How can I do that?

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:50:08+00:00Added an answer on June 15, 2026 at 2:50 pm

    The problem was solved with adding a else statement on the validation, if the validation was successfull I’d return the data to the rendering layout If something else on the validation failed.

    if (!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL))
    {
        $data['errors'][] = 'E-mail not valid';
    }
    else
    {
        $data['post']['email'] = $_POST['email'];
    }
    

    Then I’d simply pass back the $data array, containing the post.email variable and outputting it on the screen.

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