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Home/ Questions/Q 8697731
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T01:35:35+00:00 2026-06-13T01:35:35+00:00

When adding a node to a linked list I guess the idea would be

  • 0

When adding a node to a linked list I guess the idea would be as follows:

Declare newNode 
Add to the front if front == null
else if there is already a node in the list

However this does not seem to work

public boolean add (E e) {

  ListNode<E> newNode = new ListNode<E>(e,null);

  if (front == null){
      front = newNode;
      rear = newNode;
      objectCount++;
      return true;
  }

      front.next = newNode;
      rear.next = newNode;
      rear = newNode;
      objectCount++;
      return true;
}

but when I run this for the list “a”,”b”,”c”,”d”,”e” it doesn’t return a list size of 5 but of size 2. What’s going wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T01:35:36+00:00Added an answer on June 13, 2026 at 1:35 am

    You’re adding the new node next to your front and your rear nodes. In order to solve the problem, you should just add it to the rear node (assuming your list will only accept new values in the rear).

    //front.next = newNode;
    rear.next = newNode;
    rear = newNode;
    objectCount++;
    return true;
    
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