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Home/ Questions/Q 1026225
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T12:02:59+00:00 2026-05-16T12:02:59+00:00

When adding an item in my database, I need it to auto-determine the value

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When adding an item in my database, I need it to auto-determine the value for the field DisplayOrder. Identity (auto-increment) would be an ideal solution, but I need to be able to programmatically change (UPDATE) the values of the DisplayOrder column, and Identity doesn’t seem to allow that. For the moment, I use this code:

CREATE PROCEDURE [dbo].[AddItem]

AS

DECLARE @DisplayOrder INT

SET @DisplayOrder = (SELECT MAX(DisplayOrder) FROM [dbo].[MyTable]) + 1

INSERT INTO [dbo].[MyTable] ( DisplayOrder ) VALUES ( @DisplayOrder )

Is it the good way to do it or is there a better/simpler way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T12:03:00+00:00Added an answer on May 16, 2026 at 12:03 pm

    A solution to this issue from “Inside Microsoft SQL Server 2008: T-SQL Querying”

    CREATE TABLE dbo.Sequence(
     val int IDENTITY (10000, 1) /*Seed this at whatever your current max value is*/
     )
    
    GO
    
    CREATE PROC dbo.GetSequence
    @val AS int OUTPUT
    AS
    BEGIN TRAN
        SAVE TRAN S1
        INSERT INTO dbo.Sequence DEFAULT VALUES
        SET @val=SCOPE_IDENTITY()
        ROLLBACK TRAN S1 /*Rolls back just as far as the save point to prevent the 
                           sequence table filling up. The id allocated won't be reused*/
    COMMIT TRAN
    

    Or another alternative from the same book that allocates ranges easier. (You would need to consider whether to call this from inside or outside your transaction – inside would block other concurrent transactions until the first one commits)

    CREATE TABLE dbo.Sequence2(
     val int 
     )
    
    GO
    
    INSERT INTO dbo.Sequence2 VALUES(10000);
    
    GO
    
    CREATE PROC dbo.GetSequence2
    @val AS int OUTPUT,
    @n as int =1
    AS
    UPDATE dbo.Sequence2 
    SET @val = val = val + @n;
    
    SET @val = @val - @n + 1; 
    
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