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Home/ Questions/Q 6177991
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T00:23:35+00:00 2026-05-24T00:23:35+00:00

When allocating and then attempting to access an array of pointers to pointers: void

  • 0

When allocating and then attempting to access an array of pointers to pointers:

void tester(char ***p)
{
    int i;
    char **pp;

    pp = *p;
    pp = calloc(10, sizeof(*pp));

    for (i = 0; i < 10; i++)
        printf("%d = %p\n", i, pp[i]);

            *p = pp;
}

void tester_broken(char ***p)
{
    int i;

    *p = calloc(10, sizeof(**p));

    for (i = 0; i < 10; i++)
        printf("%d = %p\n", i, *p[i]);
}

int main(void)
{ 
    char **a;

    tester(&a);
    tester_broken(&a);

    return 0;
}

Can anyone explain why one of these works and the other seg faults?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T00:23:36+00:00Added an answer on May 24, 2026 at 12:23 am

    It’s a precedence problem. Try:

    void tester_fixed(char ***p)
    {
        int i;
    
        *p = calloc(10, sizeof(**p));
    
        for (i = 0; i < 10; i++)
            printf("%d = %p\n", i, (*p)[i]);
    }
    

    The bracket operator (array subscripting) binds tighter than the asterisk operator (dereference). The parentheses make your intent explict.

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