Question

When concatenate php variable result not showing.

$a = 5;
$b = 4;
$o = '+';

echo $a.$o.$b;
result showing 5+4; but i want show result 9 

How can i do this, anybody can help me out.
Thanks in advance.

Answer 1

‘+’ is a string, so if you concate it with a number you get a string. You have to look into the value:

if ($o == '+') {
    echo $a + $b;
}

Or what you probably want:

switch ($o) {
    case "+":
        echo $a + $b;
        break;
    case "-":
        echo $a - $b;
        break;
    case "*":
        echo $a * $b;
        break;
    case "/":
        echo $a / $b;
        break;
    default:
        echo 0;
}