Question

When creating a process in VB6 (related to this question:), I’m using the following struct:

Private Type STARTUPINFO       cb As Long       lpReserved As String       lpDesktop As String       lpTitle As String       dwX As Long       dwY As Long       dwXSize As Long       dwYSize As Long       dwXCountChars As Long       dwYCountChars As Long       dwFillAttribute As Long       dwFlags As Long       wShowWindow As Integer       cbReserved2 As Integer       lpReserved2 As Long       hStdInput As Long       hStdOutput As Long       hStdError As Long    End Type 

Before I start my process, what needs to happen to STARTUPINFO.hStdOutput in order for my VB6 app to read the output of my hosted process?

Thanks!!

Answer 1

Following up this other question by the OP, I post an alternative method to execute a command and get hold of stdout:

' References: 'Windows Script Host Shell Object Model' '  Public Declare Sub Sleep Lib 'kernel32' Alias 'Sleep' ( _   ByVal dwMilliseconds As Long)  Function ExecuteCommand(cmd As String, ExpectedResult as Long) As String   Dim shell As New IWshRuntimeLibrary.WshShell   Dim exec As IWshRuntimeLibrary.WshExec    Set exec = shell.Exec(cmd)   While exec.Status = 0      Sleep 100   Wend    If exec.ExitCode = ExpectedResult Then     ExecuteCommand = exec.StdOut.ReadAll   Else     ExecuteCommand = vbNullString     ' or whatever '   End End Function