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Home/ Questions/Q 8706633
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:39:41+00:00 2026-06-13T03:39:41+00:00

When designing a class that can be moved but not copied, it’s natural to

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When designing a class that can be moved but not copied, it’s natural to declare the copy constructor as private. When having only movable and trivially copyable objects as instance members, it makes sense to allow the compiler to implicitly generate the move constructor.

However, when supporting both VS11 and G++4.7 I found an incompatibility:

  • VS11 requires explicitly defined move constructors
  • G++ requires explicit move constructors to have either matching public copy constructor or the noexcept keyword.
  • VS11 doesn’t support the noexcept keyword.

As you can see, this places me in a bit of a pickle. My class must not be copied. I must support both VS11 and MinGW / GCC. I need my class to be movable.

Have I misunderstood something, or is there a way around this tiny problem? Can I make compilation fail if a call to the copy constructor is generated? Any better solution to this problem?

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:39:43+00:00Added an answer on June 13, 2026 at 3:39 am

    If you add this to the source file

    #ifdef _MSC_VER
    #define noexcept
    #endif
    

    You will be able to define it as noexcept on GCC but VC++ will ignore noexcept.

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