Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6032147
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T05:17:28+00:00 2026-05-23T05:17:28+00:00

When executing this instruction I got an exception LFS ESI,PWORD PTR [EBP+12] From this

  • 0

When executing this instruction I got an exception

LFS   ESI,PWORD PTR [EBP+12]

From this page http://wiki.osdev.org/Double_Fault#Double_Fault
Any PUSH or POP instruction or any instruction using ESP or EBP as a base register is executed, while the stack address is not in canonical form.

So i think it should be an Stack-Segment Fault here.
But the system gives an general protection exception(0D).

Could anyone tell me why the result is this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T05:17:28+00:00Added an answer on May 23, 2026 at 5:17 am

    General protection fault for an LFS occurs when:

    1. the segment selector index you are
      trying to load is not with the
      descriptor table limits
    2. the segment is in the descriptor
      table, but it’s not a readable data
      segment
    3. your privilege level is higher
      (meaning less privilege) that the
      privilige level for the descriptor.

    So, the problem is not the instruction itself, but the segment descriptor table.

    See chapter 3 in the Intel Software Developer’s Manual Volume 3A:
    http://www.intel.com/products/processor/manuals/?wapkw=(Intel+64+and+IA-32+Architectures)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I just got done walking through the install instructions on this page: http://grails.org/plugin/spring-security-facebook I
I'm executing a query like this select field from table; In that query, there
I am writing History.newItem(step2) but even after executing this instruction the method it should
Executing this code: mainLyr = [[CALayer layer] retain]; [mainLyr setFrame:CGRectMake(0.0,0.0,23.0,23.0)]; in debugger, I found
I am executing this statement under while (($data=fgetcsv($this->fin,5000,;))!==FALSE) Now what I want in else
I have an awesome trouble with Gem. After executing this command: rm -f /usr/local/lib/ruby/gems/1.9.1/cache/*
Why is this script executing the string in the if statement: #!/bin/bash FILES=* STRING=''
This code below is for executing ls -l | wc -l. In the code,
I currently use this function to wrap executing commands and logging their execution, and
When a pc first boots up, it starts executing at physical address 0xffff0. This

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.