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Home/ Questions/Q 372477
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Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T14:12:52+00:00 2026-05-12T14:12:52+00:00

When grouping is there a simple way to get the first or top value

  • 0

When grouping is there a simple way to get the first or top value out of a column. In the following example I want the last value in [Text] if sorted by [Date] descending.

SELECT 
   [Id],
   MAX([Date]),
   TOP 1 [Text],  <-- How do I do do this
   COUNT(*)
FROM
   [ExampleTable]
GROUP BY [Id]
ORDER BY [Date] DESC

Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T14:12:52+00:00Added an answer on May 12, 2026 at 2:12 pm

    If you want the text corresponding to that [Id] & that [MaxDate], you can do this:

    SELECT T2.*, T1.Text
    FROM [ExampleTable] T1
         JOIN (SELECT 
                   [Id],
                   MAX([Date]) MaxDate,
                   COUNT(*) Cnt
                 FROM
                   [ExampleTable]
             GROUP BY [Id]) T2
         ON T1.Id = T2.Id AND T1.Date = T2.MaxDate
    ORDER BY [Date] DESC
    

    if [Id] & [Date] form a primary key you will have a single row per (Id, Date) other wise many. If you really want one, either you put other constraints or use MAX or MIN::

    SELECT T2.*, MAX(T1.Text) Text -- or MIN(T1.Text)
    FROM [ExampleTable] T1
         JOIN (SELECT 
                   [Id],
                   MAX([Date]) MaxDate,
                   COUNT(*) Cnt
                 FROM
                   [ExampleTable]
             GROUP BY [Id]) T2
         ON T1.Id = T2.Id AND T1.Date = T2.MaxDate
    GROUP BY T2.*
    ORDER BY [Date] DESC
    

    If you want just a value for Text you can use MAX or MIN:

    SELECT 
       [Id],
       MAX([Date]),
       MAX([Text]),
       COUNT(*)
    FROM
       [ExampleTable]
    GROUP BY [Id]
    ORDER BY [Date] DESC
    
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